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AQA A2 Chemistry C23 Transition Metal Kerboodle Answers.

This page contains the AQA A2 Chemistry C23 Transition Metal Questions and kerboodle answers for revision and understanding.This page also contains the link to the notes and video for the revision of this topic.
 
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C23.1 The general properties of transition metals AQA A2 Chemsitry C23 Transition Metals Kerboodle Answers: Page No. 105

1 a a Mn2+ ion 1s2 2s2 2p6 3s2 3p6 3d5 b a Mn3+ ion 1s22s22p6 3s2 3p6 3d4 2 a 1s22s2 2p6 3s2 3p6 b The two 4s electrons c One of the 3d electrons

23.2 Complex formation and the shape of complex ions AQA A2 Chemsitry C23 Transition Metals Kerboodle Answers : Page No. 109

1 a i [Cu(H2O)6]2+ Octahedral ii [Cu(NH3)6]2+ Octahedral iii [CuCl4 ]2- Tetrahedral b  6,6,4 c Cl is a larger ligand than either ammonia or water, so fewer ligands can fit around the metal ion. 2. a The rwo negatively charged oxygen atoms. because they have lone pairs of electrons.
c Bidentate

23.3 Coloured ions AQA A2 Chemsitry C23 Transition Metals Kerboodle Answers : Page No. 112

1 a The copper ion has part-filled ct-orbitals, so electrons can move from one d-orbital to another and absorb light. Zinc has full d-orbitals. b Blue c They are absorbed. 2 a Which mixture absorbs most light? 5:5 b 5:5 c [NiEDTA]2-

23.4 Variable oxidation states of transition elements AQA A2 Chemsitry C23 Transition Metals Kerboodle Answers : Page No. 118

1 a b This low oxidation state can be oxidised by air. 2 0.0698 g 3 Ee- for the reaction: Cl2(g) + 2e- → 2cl is + 1.36 V, but Ee-for the reaction of Cr20 7 and c1-and is 0.03 V. Therefore the reaction is not feasible. Hence potassium dichromate(VI) will nor oxidise chloride ions ro chlorine.

23.5 Catalysis AQA A2 Chemsitry C23 Transition Metals Kerboodle Answers : Page No. 122

1 a Homogeneous catalysts are in the same phase as the reactants, heterogeneous catalysts are in a different phase from the reactants. b i Heterogeneous ii Heterogeneous iii Homogeneous 2 It lowers the activation t.!nergy. This means that reactions can be carried out at a lower temperature than without tht.! catalyst, so saving energy and money. 3 First. iron(III) oxidises iodide ro iodine, itself being reduced to iron(ll): 2Fe3+(aq) + 21-(aq) _, 2Pe2+(aq) + 1(aq) 2 Then the peroxodisulfate ions oxidise rhe iron(II) back to iron(Ill): S20/-(aq) + 2Fe2+(aq) _, 2SO/-(aq) + 2Fe3+(aq) Catalyst is needed since the reaction is slow. The reaction is slow since both reactants are negative ions. These ions will repel each other, reducing the chance of effective collisions. 4 5Mn3•(aq) + 4H20(1) 2Mn3•(aq) + c2o/-(aq) —. 2C02(g) + 2Mn2+(aq) 4Mn2+(aq) + Mn0-(aq) + 8W(aq) -+ Banner 2

Practice questions: Page No. 123

1 (a) 1s2 2s2 2p6 3s2 3p6 3d10 d-sub-shell / shell / orbitals / sub-level full (or not partially full) (b Atom or ion or transition metal bonded to / surrounded by one or more ligands by co–ordinate / dative (covalent) bonds / donation of an electron pair (c) H2 / hydrogen No lone / spare / non-bonded pair of electrons (d) (i)
 +2 OR 2+ OR Pd2+
(ii) Tetrahedral
  • Square planar
2 (a) (ll) ions are blue. (i) Absorbs (certain frequencies of) (white) light / photons
  • D-electrons excited / promoted
  • The colour observed is the light not absorbed / light reflected / light transmitted
(ii) E is the energy gained by the (excited) electrons (of Cu2+)
  • h (Planck’s) constant
  • ν frequency of light (absorbed by Cu2+ (aq))
(iii)
[Cu(H2O)6]2+ + 4Cl → [CuCl4]2- + 6H2O Tetrahedral Cl / Cl / chlorine too big (to fit more than 4 round Cu)
(b) Lone pair(s) on O/ O (c) (i) [Cu(H2O)6]2+ + 2C2O42- → [Cu(C2O4)2(H2O)2]2- + 4H2O
  • Product correct
  • Equation balanced
  • 6
  • Octahedral
(ii) 900 3 (a) A ligand is a species which can donate a pair of electrons to a metal ion.
  • A co-ordinate bond is a covalent bond in which both electrons are donated by one atom.
(b) (i) [Co(H2O)6]2+ + 4Cl → [CoCl4]2- + 6H2O Pink                                blue (ii) [Co(NH3)6]2+ + 3NH2CH2CH2NH2 → [Co(NH2CH2CH2NH2)3]2+ + 6NH3
  • More molecules and/or ions formed.
  • Increase in entropy because the reaction involves an increase in the number of molecules and ions.
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